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Event Brief

Jaxon Smith-Njigba Wins Offensive Player of the Year

The Seahawks celebrate Jaxon Smith-Njigba's record-setting season.
WHO: Jaxon Smith-Njigba
WHAT: Claims Offensive Player of the Year award
WHEN: Feb 5, 2026 at 10:39 PM ET
WHERE: Seattle
WHY: After a record-setting season
Sources (1): CBS Sports

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